Hello Geert,
Together with your additional information, I think I can provide you with the math.
Code:
- with
STAALNR = 100*INO + CNO
INO = round(([STAALNR]/100)-0.5)
100*INO = ([STAALNR]/100)-0.5)*100
CNO = [STAALNR]-100*INO
- follows
0 == ([STAALNR]-round(([STAALNR]/100)-0.5)*100) - (round(([STAALNR]/100)-0.5)-round((round(([STAALNR]/100)-0.5)/97)-0.5)*97)
0 == ([STAALNR]-round(([STAALNR]/100)-0.5)*100) - (round(([STAALNR]/100)-0.5)-round((round(([STAALNR]/100)-0.5)/DNO)-0.5)*DNO)
0 == ([STAALNR]-100*INO) - (round(([STAALNR]/100)-0.5)-round((round(([STAALNR]/100)-0.5)/DNO)-0.5)*DNO)
0 == ([STAALNR]-100*INO) - (INO-round((INO/DNO)-0.5)*DNO)
0 == (CNO) - (INO-round((INO/DNO)-0.5)*DNO)
- with:
INOc = INO cleared off the remainder of DNO, so that INOc rem DNO = 0
INOc = round((INO/DNO)-0.5)*DNO
- follows:
0 == CNO - (INO-INOc)
- with:
INOr = INO remainder
INOr = INO-INOc
- follows:
0 == CNO - INOr
With the above transformations, the factual connection has become more or less clear.
And in my opinion, it is correct so far.
The formal calculation based on the underlying values INO, CNO, and DNO is therefore as follows:
0 == (CNO) - (INO-round((INO/DNO)-0.5)*DNO)
Question 1:
Do you agree with the calculations and the illustration, and what do you think about them?
A request in the form of Question 2:
Could you please evaluate how widespread this control method actually is (institutions actually using it)?
Re: Asian hornet.
You are performing a really important and great work.
The Asian hornet 'vespa velutina' has also spread to Germany.
In France, attempts are being made to combat the Asian hornet, among other things, through large-scale trapping operations using baited bottles.
Such a practice would not be permitted in Germany, as native and endangered insects might also die in the bottles.
Best regards, Ingmar Vack